[tex]A = \left[\begin{array}{cc}3&4\\0&-2\end{array}\right] \\A^{-1}=\frac{1}{det~A} \left[\begin{array}{cc}-2&-4\\0&3\end{array}\right]\\A^{-1}=\frac{1}{(3\times-2)-(4\times0)} \left[\begin{array}{cc}-2&-4\\0&3\end{array}\right]\\A^{-1}=\frac{1}{-6} \left[\begin{array}{cc}-2&-4\\0&3\end{array}\right]\\A^{-1}=\left[\begin{array}{cc}\frac{1}{3} &\frac{2}{3} \\0&-\frac{1}{2} \end{array}\right][/tex]
[tex]B= \left[\begin{array}{cc}-1&3\\4&-6\end{array}\right]\\B^{-1}=\frac{1}{det~B}\left[\begin{array}{cc}-6&-3\\-4&-1\end{array}\right] \\B^{-1}=\frac{1}{(-6\times-1)-(-3\times-4)}\left[\begin{array}{cc}-6&-3\\-4&-1\end{array}\right] \\B^{-1}=\frac{1}{6-12}\left[\begin{array}{cc}-6&-3\\-4&-1\end{array}\right] \\B^{-1}=\frac{1}{-6}\left[\begin{array}{cc}-6&-3\\-4&-1\end{array}\right] \\B^{-1}=\left[\begin{array}{cc}1&\frac{1}{2} \\\frac{2}{3} &\frac{1}{6} \end{array}\right][/tex]
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